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Soil Mechanics and Foundation Engineering - Engineering

Q1:

If the specific gravity of a soil particle of 0.05 cm diameter is 2.67, its terminal velocity while settling in distilled water of viscosity, 0.01 poise, is

A 0.2200 cm/sec

B 0.2225 cm/sec

C 0.2250 cm/sec

D 0.2275 cm/sec

E 0.2300 cm/sec

ANS:D - 0.2275 cm/sec

To, Calculate Terminal Velocity.

V = Terminal Velocity.
D = Diameter Of a Particle.
g = Acceleration Of Gravity.
v = Viscosity Of Medium.
dp = Density Of Particle.
dm = Density Of Medium. (g/18*viscosity )*(G-1) * (d*d).
(9.81/18*0.01) * (2.67-1)* (0.05*0.05),
Answer 0.2275 cm/sec Settling velocity = (g/18)(ρs - ρw)(d^2/μ).
= (9.81/18) * (2.67-1) * (((0.05x10^-2)^2)/(0.01x10^-4),
= 0.2275 cm/sec. Terminal velocity v = (d^2/18*viscosity) * (unit wt of water (G of soil - G of fluid)).
=> (5 * 10^-4) ^ 2/(18 * 10^-4 kn.s/m^2) * (9.81 (2.67 - 1))
= .002275 m/s.
= .2275 cm/s.