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Mass Transfer

Q1:

If the specific heats of a gas and a vapor are 0.2KJ/Kg.°K and 1.5 KJ/Kg.°K respectively, and the humidity is 0.01; the humid heat in KJ/°Kg. is

A 0.31

B 0.107

C 0.017

D 0.215

ANS:D - 0.215

To find the humid heat, we need to use the formula: Humid Heat=(Specific Heat of Dry Air+Humidity×Specific Heat of Vapor)Humid Heat=(Specific Heat of Dry Air+Humidity×Specific Heat of Vapor) Given:

  • Specific heat of dry air = 0.2 KJ/Kg.°K
  • Specific heat of vapor = 1.5 KJ/Kg.°K
  • Humidity = 0.01
Let's calculate: Humid Heat=(0.2+0.01×1.5)Humid Heat=(0.2+0.01×1.5) Humid Heat=(0.2+0.015)Humid Heat=(0.2+0.015) Humid Heat=0.215 KJ/°KgHumid Heat=0.215KJ/°Kg So, the humid heat is 0.215 KJ/°Kg. Therefore, the closest option is 0.215.



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