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Problems on HCF and LCM

Q1: If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:

A
55
601

B
601
55

C
11
120

D
120
11

ANS:C -

11
120

Let the numbers be a and b. Then, a + b = 55 and ab = 5 x 120 = 600.

 The required sum = 1 + 1 = a + b = 55 = 11
a b ab 600 120



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