Q1: If the total head of the nozzle of a pipe is 37.5 m and discharge is 1 cumec, the power generated is

ANS:C - 500 H.P.

To calculate the power generated by the fluid flowing through the nozzle of a pipe, we can use the formula for hydraulic power: P=γQH Where:

• P is the power,
• γ is the specific weight of the fluid (weight per unit volume),
• Q is the discharge rate,
• H is the total head.

Given:

• Discharge Q=1m3/s
• Total head H=37.5m

To compute the specific weight γ, we need to know the density of the fluid. Assuming the fluid is water, with a density of 1000kg/m^3 (approximately), the specific weight γ would be 9.81kN/m3. Now, let's calculate the power: P=(9.81kN/m3)×(1m3/s)×(37.5m) P=368.625 kW To convert kilowatts (kW) to horsepower (HP), we can use the conversion factor: 1 kW = 1.341 HP P=368.625 kW×1.341 HP/kW≈494.06 HP Therefore, the power generated by the fluid flowing through the nozzle of the pipe is approximately 494.06HP. Based on the given options, the closest value is 500 HP. Therefore, the answer is approximately  HP500