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Parallel Circuits - Engineering

Q1:

If there are a total of 120 mA into a parallel circuit consisting of three branches, and two of the branch currents are 40 mA and 10 mA, the third branch current is

A 50 mA

B 70 mA

C 120 mA

D 40 mA

ANS:B - 70 mA

In parallel circuits the current is dividing,

I = i1+i2+i3.

So 120 = 40+10+i3.

So i3 = 120-50.

i3 = 70ma.