Networks Analysis and Synthesis - Engineering

Q1:

If V = 20 + j20, then loge(A) A is

A 3.342 + j 45

B 28.28 ∠45°

C 400 ∠45°

D 3.342 + j 0.785

ANS:D - 3.342 + j 0.785

20 x j 20 = 28.28 Ð45° loge V = loge (28.28) + = 3.342 j.785.