If voids ratio is 0.67, water content is 0.188 and specific gravity is 2.68, the degree of saturation of the soil, is

ANS:D - 75%

Gw = SE.
S = GW/e.
S = 2.68x0.188/0.67.
S = 0.75x100.
S = 75%. Given fundamental equation e =WG/Sr.
Then given;
e - o.67
G - 2.68
W - 0.188
Then find Sr = WG/e.
0.188 * 2.68/0.67,
= 75%.