If X = 1 in the logic equation [X + Z { Y + (Z + X Y)}] { X + Z (X + Y)} = 1, then-A-Y = ZB-Y = ZC-Z = 1D-Z = 0-D-Z = 0

D Z = 0 [1 + z{y + z + y}][0 + z] = 1, z = 1, z = 0.