If x1[n] x1(z) with ROC = R1 and x2[n] x2(z) with ROC = R2 then ROC for x1[n] + x2[n] will be __________ (where Ri → Region of convergence and x1[n] and x2[n] are causal).-A-R1 ∩ R2B-R1 ∪ R2C-(R1 ∪ R2) ∩ (R1)D-(R1 ∩ R2) ∪ (R1)-A-R1 ∩ R2

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If x1[n]  x1(z) with ROC = R1 and x2[n]  x2(z) with ROC = R2 then ROC for x1[n] + x2[n] will be __________ (where Ri → Region of convergence and x1[n] and x2[n] are causal).-A-R1 &cap; R2B-R1 &cup; R2C-(R1 &cup; R2) &cap; (R1)D-(R1 &cap; R2) &cup; (R1)-A-R1 &cap; R2

APTITUDE CRACK · Accepted Answer

A R1 &cap; R2  R1 ∩ R2, Suppose R1 for x1(n) be Then ROC for x1(n) + x2(n) R1 ∩ R2 (R1 &lt; R2) Then ROC for x1(n) + x2(n) R1 ∩ R2(R1 &lt; R2)

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If x₁[n] x₁(z) with ROC = R₁ and x₂[n] x₂(z) with ROC = R₂ then ROC for x₁[n] + x₂[n] will be __________ (where R_i → Region of convergence and x₁[n] and x₂[n] are causal).

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If x1[n] x1(z) with ROC = R1 and x2[n] x2(z) with ROC = R2 then ROC for x1[n] + x2[n] will be __________ (where Ri → Region of convergence and x1[n] and x2[n] are causal).

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If x₁[n] x₁(z) with ROC = R₁ and x₂[n] x₂(z) with ROC = R₂ then ROC for x₁[n] + x₂[n] will be __________ (where R_i → Region of convergence and x₁[n] and x₂[n] are causal).

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