Exam Questions Papers - Engineering

Q1:

In a 4 bit weighted resistor D/A converter, the resistor value corresponding to LSB is 32 kΩ. The resistor value corresponding to MSB will be

A 32 KΩ

B 16 KΩ

C 8 KΩ

D 4 KΩ

ANS:D - 4 KΩ

2n - 1 R = 32 K&Omeg; n = 4 ⇒ 8R = 32 R = 4 KΩ.