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Chemical Engineering Basics - Engineering

Q1:

In a forced draft cooling tower, water is cooled from 95 to 80°F by exposure to air with a wet bulb temperature of 70°F. In this case, the

A range is 15°F.

B approach is 10°F.

C both (a) & (b).

D neither (a) nor (b).

ANS:C - both (a) & (b).

To determine the range and approach in a cooling tower, we need to understand the definitions:

  1. Range: The range is the temperature difference between the hot water inlet temperature and the cold water outlet temperature.
  2. Approach: The approach is the temperature difference between the cold water outlet temperature and the wet bulb temperature of the air.
Given:
  • Hot water inlet temperature (Ti) = 95°F
  • Cold water outlet temperature (To) = 80°F
  • Wet bulb temperature of air (Twb) = 70°F
Let's calculate the range and approach:
  1. Range: Range = Ti - To = 95°F - 80°F = 15°F
  2. Approach: Approach = To - Twb = 80°F - 70°F = 10°F
So, based on the calculations:
  • The range is 15°F.
  • The approach is 10°F.
Therefore, the correct answer is: neither (a) nor (b).