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RL Circuits - Engineering

Q1:

In a parallel RL circuit, there are 3 A rms in the resistive branch and 3 A rms in the inductive branch. The total rms current is

A 6 A

B 424 mA

C 4.24 A

D 42.4 A

ANS:C - 4.24 A

Irms = √(√(i1rms)+ √(i2rms)) Because i1rms=i2rms=3amps.
Irms = √(2√(irms)),
Irms = √(2)*irms,
Irms = 1.414*3 = 4.2a.