In a second order system ωn = 10 rad/sec and ζ = 0.1, then ωd =-A-9.1 rad/secB-9.95 rad/secC-9 rad/secD-1 rad/sec-B-9.95 rad/sec

Question

In a second order system &omega;n = 10 rad/sec and &zeta; = 0.1, then &omega;d =-A-9.1 rad/secB-9.95 rad/secC-9 rad/secD-1 rad/sec-B-9.95 rad/sec

APTITUDE CRACK · Accepted Answer

B 9.95 rad/sec  .root { background image: url(/_files/images/chemical engineering/common/root.gif); background position: top left; background repeat: no repeat; padding left: 10px; padding top: 1px; } Wd = ωn1 ζ2 = 10 (1 0.01)05 = 9.95 rad/s.

Automatic Control Systems - Engineering

In a second order system ω_n = 10 rad/sec and ζ = 0.1, then ω_d =

For help Students Orientation
Mcqs Questions

Quick Links

Newsletter

Automatic Control Systems - Engineering

In a second order system ωn = 10 rad/sec and ζ = 0.1, then ωd =

Solution

For help Students Orientation Mcqs Questions

In a second order system ω_n = 10 rad/sec and ζ = 0.1, then ω_d =

For help Students Orientation
Mcqs Questions