Download Aptitude Crack
img not found img not found

Series-Parallel Circuits

Q1: In a series–parallel circuit, individual component power dissipations are calculated using:

A individual component parameters

B a percent of the voltage division ratio squared

C total current squared multiplied by the resistor values

D a percent of the total power depending on resistor ratios

ANS:A - individual component parameters

It will depend upon component parameter because if we take two resistance values are 20 ohms and 100k.power dissipation= v*i
v=i*r
then p=i*i*r
so p is proportional to component parameter
In 20ohms resistor power dissipation less than 100k



img not found
img

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.