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Series-Parallel Circuits - Technical MCQs

Q1:

In a series–parallel circuit, individual component power dissipations are calculated using:

A individual component parameters

B a percent of the voltage division ratio squared

C total current squared multiplied by the resistor values

D a percent of the total power depending on resistor ratios

ANS:A - individual component parameters

It will depend upon component parameter because if we take two resistance values are 20 ohms and 100k.power dissipation= v*i
v=i*r
then p=i*i*r
so p is proportional to component parameter
In 20ohms resistor power dissipation less than 100k