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RLC Circuits and Resonance - Engineering

Q1:

In a series RLC circuit that is operating above the resonant frequency, the current

A lags the applied voltage

B leads the applied voltage

C is in phase with the applied voltage

D is zero

ANS:A - lags the applied voltage

Resonant frequency(fr) = 1/(2 * 3.14 * (LC)1/2,
Take that root.
Given that RLC circuit is above the fr then we know XL > XC in case fr is more then current must be low and that case current should be lags by applied voltage.