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Mass Transfer - Engineering

Q1:

In a solution containing 0.30 Kg mole of solute and 600 kg of solvent, the molality is

A 0.50

B 0.60

C 2

D 1

ANS:A - 0.50

Molality (𝑚m) is defined as the number of moles of solute per kilogram of solvent. Given:

  • Number of moles of solute (𝑛n) = 0.30 kg mole
  • Mass of solvent (𝑚solventmsolvent​) = 600 kg
Molality (𝑚m) can be calculated using the formula: 𝑚=𝑛𝑚solventm=msolvent​n​ Substituting the given values: 𝑚=0.30 kg mole600 kgm=600kg0.30kg mole​ 𝑚=0.30600 mol/kgm=6000.30​mol/kg 𝑚=0.0005 mol/kgm=0.0005mol/kg Therefore, the molality of the solution is 0.0005 mol/kg0.0005mol/kg, which is equivalent to 0.5 mol/kg. So, the correct option is 0.50.