In an R-L circuit excited by a battery of voltage E, the current and voltage across resistor are 1- e-t and 2(1 - e-t) respectively. If there were an initial current of 2 A in the inductance, the voltage across resistance would have been-A-1 e tB-2 2e tC-2 + 2e tD-4 4e t-C-2 + 2e t

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C 2 + 2e t From the given data R = 2&Omega;, L = 2H and E = 2V. Because of initial current of 2A, i(t) = 1 e t + 2e t = 1 + e t. Therefore, VR = 2(1 + e t).

Networks Analysis and Synthesis - Engineering

In an R-L circuit excited by a battery of voltage E, the current and voltage across resistor are 1- e^-t and 2(1 - e^-t) respectively. If there were an initial current of 2 A in the inductance, the voltage across resistance would have been

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Networks Analysis and Synthesis - Engineering

In an R-L circuit excited by a battery of voltage E, the current and voltage across resistor are 1- e-t and 2(1 - e-t) respectively. If there were an initial current of 2 A in the inductance, the voltage across resistance would have been

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For help Students Orientation Mcqs Questions

In an R-L circuit excited by a battery of voltage E, the current and voltage across resistor are 1- e^-t and 2(1 - e^-t) respectively. If there were an initial current of 2 A in the inductance, the voltage across resistance would have been

For help Students Orientation
Mcqs Questions