Networks Analysis and Synthesis - Engineering

Q1:

In figure, S is closed at t = 0. At t = t1, I = 1 A and di/dt = 1 A/s. Then the value of L is

A 1 H

B 2 H

C 3 H

D 4 H

ANS:B - 2 H

i = 18(1 - e-t/L) = 6 and Hence L = 2H.