Networks Analysis and Synthesis - Engineering

Q1:

In figure, the capacitor is charged to 1 V. At t = 0 the switch is closed so that i = e-t. When i = 0.37 A, the voltage across capacitor is

A 1 V

B 0.63 V

C 0.37 V

D 0.185 V

ANS:C - 0.37 V

During discharge of capacitor vC = vR = 0.37 x 1 = 0.37 V