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Analog Electronics

Q1:
In figure the coordinates of Q point on the load line are (Neglect VBE)

A IC = 10 mA, VCE = 15 V

B IC = 5 mA, VCE = 22.5 V

C IC = 5 mA, VCE = 15 V

D IC = 10 mA, VCE = 22.5 V

ANS:A - IC = 10 mA, VCE = 15 V

Vcc-IbRb-Vbe=0.
30V-Ib(300k)=0.
*here neglect VBE*.
Ib=1x10^-4.

Ic=Beta(Ib).
*take beta as 100,
c=100(1x10^-4),
Ic=10mA.

Vcc-IcRc-Vce=0.
30V-10mA(1.5k)-Vce=0.
Vce= 15V.



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