Networks Analysis and Synthesis - Engineering

Q1:

In following circuit, steady state is reached with S open, S is closed at t = 0, the current I at t = 0+ is given by

A 9 Ω

B 6 Ω

C 7 Ω

D 10 Ω

ANS:C - 7 Ω

When steady state is reached with s open, capacitor will act as open circuit Current in 4Ω resistor will be = 6A at steady state. Voltage across 4Ω = 6 x 4 24 volt. Current in 2Ω resistor due to 6A 3A current due to 16 V, source. I = 16/2 8A, this current divide in (2 + 2) Ω is 4Ω resistor current in 2Ω resistor 4A + 3A 7A.