Networks Analysis and Synthesis - Engineering

Q1:

In the circuit shown in the figure, steady-state was reached when the switch S was open. The switch was closed at t = 0. The initial value of the current through the capacitor 2 C is

A zero

B 1 A

C 2 A

D 3 A

ANS:C - 2 A

At steady state capacitor will be open and inductor will short circuited. V across 2C will be = 12v .