Networks Analysis and Synthesis

Q1:

In the circuit shown in the figure, steady-state was reached when the switch S was open. The switch was closed at t = 0. The initial value of the current through the capacitor 2 C is

A zero

B 1 A

C 2 A

D 3 A

ANS:C - 2 A

At steady state capacitor will be open and inductor will short circuited. V across 2C will be = 12v .



img not found
img

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.