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Analog Electronics - Engineering

Q1:

In the circuit shown in the given figure, the current flowing through resistance of 100 Ω would be

A 8 mA

B 10 mA

C 20 mA

D 100 mA

ANS:A - 8 mA

Opamp vi=2v.
So using virtually ground concept another terminal also same 2v so Vc=2v.
Vcc-ic.rc=0 10-2/1k=8ma.