Series-Parallel Circuits

In the given circuit, the current flowing through R₃ equals ______.

A 10 mA

B 21.11 mA

C 90 mA

D 100 mA

ANS:A - 10 mA

By applying KVL for both loops we get following equations.

200I1-100I2=19,
-100I1+ 1000I2= -19,
so we get I1=90mA.
and I2=-10mA,
So across R3 current I2 is flowing which is 10mA.

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