Series-Parallel Circuits

Q1: In the given circuit, the current flowing through R₃ equals ______.

A 10 mA

B 21.11 mA

C 90 mA

D 100 mA

ANS:A - 10 mA

By applying KVL for both loops we get following equations.

200I1-100I2=19,
-100I1+ 1000I2= -19,
so we get I1=90mA.
and I2=-10mA,
So across R3 current I2 is flowing which is 10mA.

Share :

img not found

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.