In the given circuit, the voltage across the capacitor 1 ms after the switch is closed is 11.61 V.

ANS:B - False

When the switch is closed the capacitor starts discharging through resistor. The discharge equation is. Vc=Vs*e^ (-t/rc). Substituting for Vc=15v, t=1ms, r=1. 2k & c=0. 56uf. We arrive at Vo=3. 387V.

Here 1ms specified is the elapsed time after the switch is closed, and not the time constant to check with.