Series-Parallel Circuits

Q1: In the given circuit, the voltage at point A equals ______.

A –10 V

B +1 V

C +9 V

D +10 V

ANS:D - +10 V

By KVL/Mesh analysis you can get that the currents: I1 = 0.09 A, I3 = 0.01 A, & I2=0.1 A. You can use any of these currents and perform nodal analysis on point A.

Using I1:
(19-Va)/100 = 0.09A ; Va = +10V.

Using I2:
(Va-0)/100 = 0.1A; Va = +10V.

Using I3:
(19-Va)/900 = 0.01; Va = +10V.

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