Series-Parallel Circuits

In the given circuit, the voltage dropped across R₁ equals _____.

A 1 V

B 9 V

C 10 V

D 19 V

ANS:B - 9 V

200 I1 - 100 I2= 19 --> equation 1.
-100 I1 + 1000 I2 = -19 --> equation 2.
solving equation 1 and 2 we get,
I1 =90mA and I2 = -10mA.
Voltage accross R1 will be;
Vr1 = (R1) (I1).
Vr1 = 100 X 0.09 = 9 V.

Hence its 9 volts.

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