Q1: In the given circuit, what will the voltage be across R3 25 mu.gifs after the switch is moved to position 2?

A 5.9 V

B 8.34 V

C 14 V

D 2.88 V

ANS:B - 5.9 V

I(0-)=14/940=0.0148A....Inductor gets shorted.

At position 2.
inductor starts discharging
I(t)=I(0-)*e^(-t/T)---------> (a)

put this value in (a).
The voltage of R3=560*0.01052=5.9V.

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