ANS:C - 106

To find the equivalent weight of Na2CO3Na2​CO3​ in the given reaction, we first need to understand the concept of equivalent weight. The equivalent weight of a compound is the weight of the compound that can supply or react with one mole of hydrogen ions (H⁺) or hydroxide ions (OH⁻) in a chemical reaction. The reaction given is: Na2CO3+HCl→NaHCO3+NaClNa2​CO3​+HCl→NaHCO3​+NaCl From the reaction, we can see that 1 mole of Na2CO3Na2​CO3​ reacts with 2 moles of HClHCl to form 1 mole of NaHCO3NaHCO3​ and 1 mole of NaClNaCl. The molar mass of Na2CO3Na2​CO3​ is approximately 2×23+12+3×16=106 g/mol2×23+12+3×16=106g/mol. Since Na2CO3Na2​CO3​ reacts with 2 moles of HClHCl, its equivalent weight is half its molar mass. Equivalent weight of Na2CO3=Molar mass of Na2CO32=1062=53 g/equivEquivalent weight of Na2​CO3​=2Molar mass of Na2​CO3​​=2106​=53g/equiv Therefore, the equivalent weight of Na2CO3Na2​CO3​ is 53 g/equiv.