Analog Electronics - Engineering

Q1:

Leakage current approximately doubles for every 10°C increase in the temperature of a transistor has ICBO = 400 nA at 25°C, then its leakage current at 80°C

A 10 μA

B 18 μA

C 20 μA

D 15 μA

ANS:B - 18 μA

ICBO = (400 x 10-9) 2(80-25)/10 = 18 μA.