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UPSC Civil Service Exam Questions - Engineering

Q1:

<div class="bix-td-qtxt table-responsive w-100">What are the magnitudes of horizontal and vertical support reactions, respectively at support. A of the frame shown in figure below ?<br><img src="/_files/images/civil-engineering/upsc-civil-service-exam-questions/64-1590.png"></div>

A 16 kN, 18 kN

B 16 kN, 6 kN

C 6 kN, 16 kN

D 8 kN, 6 kN

ANS:B - 16 kN, 6 kN

Taking moment at B: therefore, we have, Ra(4)+16(1.5)-24(2)=0, 4Ra=24; Ra= 6KN.
Summation of horizontal force = 0= 16KN + Ha=0; Ha = 16Kn.