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Numbers - General Aptitude

Q1:

On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:

A 10

B 11

C 12

D 13

ANS:A - 10

Clearly, (2272 - 875) = 1397, is exactly divisible by N. Now, 1397 = 11 x 127  The required 3-digit number is 127, the sum of whose digits is 10.