- Mass Transfer - Section 1
- Mass Transfer - Section 2
- Mass Transfer - Section 3
- Mass Transfer - Section 4
- Mass Transfer - Section 5
- Mass Transfer - Section 6
- Mass Transfer - Section 7
- Mass Transfer - Section 8
- Mass Transfer - Section 9
- Mass Transfer - Section 10
- Mass Transfer - Section 11
- Mass Transfer - Section 12
- Mass Transfer - Section 13
- Mass Transfer - Section 14


Mass Transfer - Engineering
Q1: Penetration theory states that the mass transfer co-coefficient is equal to (where, De is diffusivity and 't' is time)A (De.t)1/2
B (De/t)1/2
C (4De/πt)1/2
D (4De/t)
ANS:C - (4De/πt)1/2 The Penetration theory states that the mass transfer coefficient (𝐾K) is proportional to the inverse square root of the diffusion time (𝑡t). Mathematically, this relationship is represented as: 𝐾∝1𝑡K∝t1 The diffusivity (𝐷𝑒De) is related to the diffusion time by the equation: 𝐷𝑒=𝑥24𝑡De=4tx2 where 𝑥x is the distance traveled by the diffusing species. Therefore, substituting the expression for 𝐷𝑒De into the relationship for 𝐾K, we get: 𝐾∝𝑥24𝑡K∝4tx2 𝐾∝𝑥2𝑡K∝2tx However, since the proportionality constant is typically determined empirically, it is common to see the equation written as: 𝐾=𝑥2𝑡K=2tx So, the correct option from the provided choices would be: (4𝐷𝑒𝜋𝑡)1/2(πt4De)1/2 |


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