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Analog Electronics - Engineering

Q1:

Percentage increase in the reverse saturation current of a diode if the temperature is increased from 25°C to 50°C

A 50%

B 500%

C 565.7%

D 575.6%

ANS:C - 565.7%

= 2(T2 - T1)/10 = 2(50-25)/10 x 100% 565.7% .