[Solved] Point out the error, if any in the program. #include<stdio.h> int main() { int P = 10; switch(P) { case 10: printf('Case 1'); case 20: printf('Case 2'); break; case P: printf('Case 2'); break; } return 0; } - Programming - C Programming - Control Instructions

Control Instructions

Q1: Point out the error, if any in the program.

#include<stdio.h>
int main()
{
    int P = 10;
    switch(P)
    {
       case 10:
       printf('Case 1');

       case 20:
       printf('Case 2');
       break;

       case P:
       printf('Case 2');
       break;
    }
    return 0;
}

A Error: No default value is specified

B Error: Constant expression required at line case P:

C Error: There is no break statement in each case.

D No error will be reported.

ANS:A - Error: No default value is specified

The compiler will report the error 'Constant expression required' in the line case P: . Because, variable names cannot be used with case statements. The case statements will accept only constant expression.

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Control Instructions

Q1: Point out the error, if any in the program.
`#include<stdio.h> int main() { int P = 10; switch(P) { case 10: printf('Case 1'); case 20: printf('Case 2'); break; case P: printf('Case 2'); break; } return 0; }`

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Control Instructions

Q1: Point out the error, if any in the program. #include<stdio.h> int main() { int P = 10; switch(P) { case 10: printf('Case 1'); case 20: printf('Case 2'); break; case P: printf('Case 2'); break; } return 0; }

Solution

For help Students Orientation Mcqs Questions

Q1: Point out the error, if any in the program.
`#include<stdio.h> int main() { int P = 10; switch(P) { case 10: printf('Case 1'); case 20: printf('Case 2'); break; case P: printf('Case 2'); break; } return 0; }`

For help Students Orientation
Mcqs Questions