[Solved] Point out the error in the following program. #include<stdio.h> #include<stdlib.h> int main() { int *a[3]; a = (int*) malloc(sizeof(int)*3); free(a); return 0; } - Programming - C Programming - Memory Allocation

Memory Allocation

Memory Allocation - General Questions
Memory Allocation - Find Output of Program
Memory Allocation - Point Out Errors
Memory Allocation - Point Out Correct Statements
Memory Allocation - True / False Questions
Memory Allocation - Yes / No Questions

Q1: Point out the error in the following program.

#include<stdio.h>
#include<stdlib.h>

int main()
{
    int *a[3];
    a = (int*) malloc(sizeof(int)*3);
    free(a);
    return 0;
}

A Error: unable to allocate memory

B Error: We cannot store address of allocated memory in a

C Error: unable to free memory

D No error

ANS:A - Error: unable to allocate memory

We should store the address in a[i]

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Memory Allocation

Q1: Point out the error in the following program.
`#include<stdio.h> #include<stdlib.h> int main() { int a[3]; a = (int) malloc(sizeof(int)*3); free(a); return 0; }`

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Memory Allocation

Q1: Point out the error in the following program. #include<stdio.h> #include<stdlib.h> int main() { int *a[3]; a = (int*) malloc(sizeof(int)*3); free(a); return 0; }

Solution

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Q1: Point out the error in the following program.
`#include<stdio.h> #include<stdlib.h> int main() { int a[3]; a = (int) malloc(sizeof(int)*3); free(a); return 0; }`

For help Students Orientation
Mcqs Questions