- Chemical Engineering Basics - Section 1
- Chemical Engineering Basics - Section 2
- Chemical Engineering Basics - Section 3
- Chemical Engineering Basics - Section 4
- Chemical Engineering Basics - Section 5
- Chemical Engineering Basics - Section 6
- Chemical Engineering Basics - Section 7
- Chemical Engineering Basics - Section 8
- Chemical Engineering Basics - Section 9
- Chemical Engineering Basics - Section 10
- Chemical Engineering Basics - Section 11
- Chemical Engineering Basics - Section 12
- Chemical Engineering Basics - Section 13
- Chemical Engineering Basics - Section 14
- Chemical Engineering Basics - Section 15
- Chemical Engineering Basics - Section 16
- Chemical Engineering Basics - Section 17
- Chemical Engineering Basics - Section 18
- Chemical Engineering Basics - Section 19
- Chemical Engineering Basics - Section 20
- Chemical Engineering Basics - Section 21
- Chemical Engineering Basics - Section 22
- Chemical Engineering Basics - Section 23
- Chemical Engineering Basics - Section 24
- Chemical Engineering Basics - Section 25
- Chemical Engineering Basics - Section 26
- Chemical Engineering Basics - Section 27
- Chemical Engineering Basics - Section 28


Chemical Engineering Basics - Engineering
Q1: Pressure required to increase the density of water by about 1% is __________ atmosphere.A 10
B 50
C 200
D 1000
ANS:C - 200 To determine the pressure required to increase the density of water by about 1%, we can use the bulk modulus of water. The bulk modulus represents the resistance of a substance to uniform compression. For water, the bulk modulus (�K) is approximately 2.2×109 N/m22.2×109N/m2. The formula relating pressure (P), bulk modulus (K), change in volume (ΔV), and original volume (V) is: P=VK⋅ΔV Given that a 1% increase in density corresponds to a 1% decrease in volume, we can calculate the change in volume using the relationship between density (ρ), mass (m), and volume (V): ρ=Vm Since density is inversely proportional to volume, a 1% increase in density implies a 1% decrease in volume. Now, to calculate the pressure (P), we can substitute the given values into the formula: P=1(2.2×109N/m2)⋅0.01 P=2.2×107N/m2 To convert the pressure from pascals to atmospheres, we can use the conversion factor: 1 atm=101325 Pa1atm=101325Pa. atm=2.2×107101325Patm=1013252.2×107 atm≈217.2Patm≈217.2 So, the pressure required to increase the density of water by about 1% is approximately 217.2217.2 atmospheres. |


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