Q1: Pressure required to increase the density of water by about 1% is __________ atmosphere.

ANS:C - 200

To determine the pressure required to increase the density of water by about 1%, we can use the bulk modulus of water. The bulk modulus represents the resistance of a substance to uniform compression. For water, the bulk modulus (�K) is approximately 2.2×109 N/m22.2×109N/m2. The formula relating pressure (P), bulk modulus (K), change in volume (ΔV), and original volume (V) is: P=VK⋅ΔV​ Given that a 1% increase in density corresponds to a 1% decrease in volume, we can calculate the change in volume using the relationship between density (ρ), mass (m), and volume (V): ρ=Vm​ Since density is inversely proportional to volume, a 1% increase in density implies a 1% decrease in volume. Now, to calculate the pressure (P), we can substitute the given values into the formula: P=1(2.2×109N/m2)⋅0.01​ P=2.2×107N/m2 To convert the pressure from pascals to atmospheres, we can use the conversion factor: 1 atm=101325 Pa1atm=101325Pa. atm=2.2×107101325Patm​=1013252.2×107​ atm≈217.2Patm​≈217.2 So, the pressure required to increase the density of water by about 1% is approximately 217.2217.2 atmospheres.