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Exceptions - Programming

Q1:

public class MyProgram 
{
    public static void throwit() 
    {
        throw new RuntimeException();
    }
    public static void main(String args[])
    {
        try 
        {
            System.out.println('Hello world ');
            throwit();
            System.out.println('Done with try block ');
        }
        finally 
        {
            System.out.println('Finally executing ');
        }
    }
}
which answer most closely indicates the behavior of the program?

A The program will not compile.

B The program will print Hello world, then will print that a RuntimeException has occurred, then will print Done with try block, and then will print Finally executing.

C
The program will print Hello world, then will print that a RuntimeException has occurred, and then will print Finally executing.

D The program will print Hello world, then will print Finally executing, then will print that a RuntimeException has occurred.

ANS:A - The program will not compile.

Once the program throws a RuntimeException (in the throwit() method) that is not caught, the finally block will be executed and the program will be terminated. If a method does not handle an exception, the finally block is executed before the exception is propagated.