ANS:A - 180

The sensible heat absorbed by 1 lb of water when it is heated from 32 to 212°F can be calculated using the specific heat capacity of water. The specific heat capacity of water is approximately 1 BTU/lb°F. The change in temperature is 212°−32°=180°212°F−32°F=180°F. So, the sensible heat absorbed is: Heat=Mass×Specific Heat×Change in TemperatureHeat=Mass×Specific Heat×Change in Temperature Heat=1 lb×1 BTU/lb°F×180°Heat=1 lb×1 BTU/lb°F×180°F Heat=180 BTUHeat=180 BTU Therefore, the sensible heat absorbed by 1 lb of water when it is heated from 32 to 212°F is approximately 180 BTU.