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Theory of Structures

Q1: Shear centre of a half circular section of radius r and of constant thickness, lies at a distance of x from the centre where x is

A

B

C

D

ANS:D -

Shear centre = b^2 h^2 t/4I.
Here,
b = d,
h = d/2.
I= π/4 d^4.

Shear centre=d^2 . (d/2)^2 . d/4 . (π/4 d^4)
= 8D/&pi.
= 4r/π.



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