Shear centre of a half circular section of radius r and of constant thickness, lies at a distance of x from the centre where x is-A-B-C-D--D-

Question

APTITUDE CRACK · Accepted Answer

D  Shear centre = b^2 h^2 t/4I. Here, b = d, h = d/2. I= &pi;/4 d^4. Shear centre=d^2 . (d/2)^2 . d/4 . (&pi;/4 d^4) = 8D/&amp;pi. = 4r/&pi;.

Theory of Structures - Engineering