System is at rest for t < 0. Vs = sin 2t. Determine v(t) for t greater than zero. -A-B-C-D--D-

D KCL at node V ∴ Natural response from s + 2, is Ae 2t For Vs = sin 2t, s = 2j Steady state response Since the system is at rest for t < 0 Now substituting t = 0, we get