Diodes and Applications

Q1: The average value of the output voltage from the circuit in the given circuit equals ___.

A 5.48 V

B 2.74 V

C 0 V

D 6.37 V

ANS:A - 5.48 V

Vs = 10v, V = 10-1.4 = 8.6v. Therefore,

Vav = Vdc = 8.6*0.636.

= 5.47v.

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