- Chemical Engineering Basics - Section 1
- Chemical Engineering Basics - Section 2
- Chemical Engineering Basics - Section 3
- Chemical Engineering Basics - Section 4
- Chemical Engineering Basics - Section 5
- Chemical Engineering Basics - Section 6
- Chemical Engineering Basics - Section 7
- Chemical Engineering Basics - Section 8
- Chemical Engineering Basics - Section 9
- Chemical Engineering Basics - Section 10
- Chemical Engineering Basics - Section 11
- Chemical Engineering Basics - Section 12
- Chemical Engineering Basics - Section 13
- Chemical Engineering Basics - Section 14
- Chemical Engineering Basics - Section 15
- Chemical Engineering Basics - Section 16
- Chemical Engineering Basics - Section 17
- Chemical Engineering Basics - Section 18
- Chemical Engineering Basics - Section 19
- Chemical Engineering Basics - Section 20
- Chemical Engineering Basics - Section 21
- Chemical Engineering Basics - Section 22
- Chemical Engineering Basics - Section 23
- Chemical Engineering Basics - Section 24
- Chemical Engineering Basics - Section 25
- Chemical Engineering Basics - Section 26
- Chemical Engineering Basics - Section 27
- Chemical Engineering Basics - Section 28


Chemical Engineering Basics - Engineering
Q1: The bulk modulus of a material with Poisson's ratio of 0.5 is equal toA 3 x Young's modulus
B Young's modulus
C infinity
D zero
ANS:C - infinity The relationship between Young's modulus (E), Poisson's ratio (ν), and bulk modulus �K) for an isotropic material is given by the following equations: K=3(1−2ν)E Given that Poisson's ratio (ν) is 0.5, we can substitute this value into the equation: K=3(1−2(0.5))E K=3(1−1)E K=3(0)E Since the denominator is 0, we have a division by zero error. This indicates that the bulk modulus (K) is undefined for a material with Poisson's ratio of 0.5. In practical terms, a material with a Poisson's ratio of exactly 0.5 is a theoretical construct and doesn't exist in real materials. Poisson's ratio for common materials typically ranges between 0 and 0.5. Therefore, the bulk modulus would not be defined for such a material. |


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