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RC Circuits - Engineering

Q1:

The complex number 40 55° is equivalent to

A 55 + j55

B 40 + j40

C 45.88 + j65.52

D 22.94 + j32.76

ANS:D - 22.94 + j32.76

A<B = A(cosB+isinB).

So here,

40<55 = 40(cos55+isin55) = 22.94+i32.76.