Q1: The cooling rate required to freeze 1 ton of water at 0°C into ice at 0°C in 24 hours is __________ BTU/hr.

ANS:B - 200

To calculate the cooling rate required to freeze 1 ton of water at 0°C into ice at 0°C in 24 hours, we need to determine the amount of heat that needs to be removed from the water to freeze it into ice. First, let's find out how much heat is required to freeze 1 ton (2000 pounds) of water into ice at 0°C:

1. The latent heat of fusion for water, which is the amount of heat required to change 1 pound of water into ice at 0°C, is approximately 144 BTU (British Thermal Units).
2. Since we have 2000 pounds of water, the total heat required to freeze 1 ton of water into ice at 0°C is: Heat = 2000 pounds * 144 BTU/pound = 288,000 BTU

Now, we need to find the cooling rate required to remove 288,000 BTU of heat from the water in 24 hours: Cooling Rate = Total Heat / Time Cooling Rate = 288,000 BTU / 24 hours ≈ 12,000 BTU/hr Therefore, the cooling rate required to freeze 1 ton of water at 0°C into ice at 0°C in 24 hours is approximately 12,000 BTU/hr. None of the provided options match this value exactly. However, the closest option is 1000 BTU/hr. Please double-check the options or the problem statement for accuracy. If 1000 BTU/hr was intended, then it would not be correct for the given scenario.