Networks Analysis and Synthesis - Engineering

Q1:

The current through a 1 mH inductance is i(t) = 2.56 x 10-2 - 4 x 103 t for 2 ≤ t ≤ 20 μ sec. The voltage across the inductor is

A 4

B 8

C 0

D 8 x 103

ANS:A - 4

1 x 10-3 (2.56 x 10-2 - 4 x 103t) = 1 x 10-3 x 4 x 103 4 volt.