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UPSC Civil Service Exam Questions

Q1: The distance between two bench marks is 1000 m. If during levelling, the total error due to collimation, curvature and refraction is found to be + 0.120 m, then the magnitude of the collimation error is

A 0.00527 m

B 0.0527 m

C 0.527 m

D 0.673 m

ANS:B - 0.0527 m

C combined = 0.0673 * d² ( C combined = C refraction + C curvature)
C combined = 0.0673 * 1² = 0.0673.
C total = 0.12.
Then, C collimation = 0.12 - 0.0673 = 0.0527.



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