The dry density of a soil is 1.5 g/cc. If the saturation water content were 50%, then its saturated density and submerged density would, respectively, be-A-1.5 g/cc and 1.0 g/ccB-2.0 g/cc and 1.0 g/ccC-2.25 g/cc and 1.25 g/ccD-2.0 g/cc and 1.50 g/cc-C-2.25 g/cc and 1.25 g/cc

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C 2.25 g/cc and 1.25 g/cc Given, rd = 1.5, w= 50%, rd=?,raub=? Rd = rt/1+w 1.5 = rt/1+.5 1.5 * 1.5=rt 2.25 = rt =&gt; Ans rsub = rsat rw. rsub = 2.25 1. Raub = 1.25. Ans.

UPSC Civil Service Exam Questions - Engineering

The dry density of a soil is 1.5 g/cc. If the saturation water content were 50%, then its saturated density and submerged density would, respectively, be

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UPSC Civil Service Exam Questions - Engineering

The dry density of a soil is 1.5 g/cc. If the saturation water content were 50%, then its saturated density and submerged density would, respectively, be

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