Download Aptitude Crack
img not found img not found

Alternating Current and Voltage

Q1: The effective value of a sine wave is equal to

A 0.707 of peak voltage

B 0.636 of peak voltage

C sin 45° of peak voltage

D both 0.707 of peak voltage and sin 45° of peak voltage

ANS:D - both 0.707 of peak voltage and sin 45° of peak voltage

Effective value mens sine wave RMS value.
So RMS VALUE =vm/root2 =Vm*1/root2 =Vm*0.1707,
And Sin 45 =1/root2 so 0.7.7*Vm.



img not found
img

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.