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Theory of Structures - Engineering

Q1:

The equivalent length of a column of length L, having one end fixed and other end hinged, is

A 2L

B L

C

D

ANS:D -

Both end hinged=l critical load= 3.14^2 * EI/L^2.
Both end fixed=l/2 critical load= 4*3.14^2 * EI/L^2.
One end fixed and other end hinged=l/(squ of 2) critical load= 2*3.14^2 * EI/L^2.
one end fixed and other end free=2l critical load= 3.14^2 * EI/4*L^2.

Both end hinged=l critical load= 3.14^2 * EI/L^2.

Both end hinged=l critical load= 3.14^2 * EI/L^2.